-5x^2+37x+72=0

Solution for -5x^2+37x+72=0 equation:

-5x^2+37x+72=0

a = -5; b = 37; c = +72;
Δ = b2-4ac
Δ = 372-4·(-5)·72
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-53}{2*-5}=\frac{-90}{-10}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+53}{2*-5}=\frac{16}{-10}
=-1+3/5
$